Page 228 - 48Fundamentals of Compressible Fluid Mechanics
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190     CHAPTER 11. EVACUATING AND FILLING A SEMI RIGID CHAMBERS

                                             Equation (11.23) can be integrated as


                                                                                                              (11.24)

                                                                                     B
                                             The integration limits are obtained by simply using the definitions of reduced pres-


                                                                             > . After the integration, equation (11.24) and


                                                                                      *
                                            rearrangement becomes      >*  >*
                                                                          '






                                                                                                              (11.25)
                                                      >*
                                            sure, at
                                                               and

                                                                             E




                                            Example 11.1:         >      %    *   >
                                            A chamber is connected to a main line with pressure line with a diaphragm and
                                                                                *
                                            nozzle. The initial pressure at the chamber is 9
 ,  and the volume is  . .
                                            Calculate time it requires that the pressure to reach 5[Bar] for two different noz-
                                                                              ] when diaphragm is erupted. Assumed the
                                            stagnation temperature at the main line is the ambient of )  .


                                              SOLUTION


                                            The characteristic time is
                                            zles throat area of 0.001, and 0.1 [
                                                                                                              (11.26)





                                             And for smaller area  $ $            $      )(

                                                       ?PO
                                                                              =)$
                                                                                              $
                                                     *
                                                      N

                                                                 ?PO
                                                                             )$
                                                               N


                                                                                    9
                                             The time is      *             )(
                                                                                    9
                                                                       >

                                                                           *
                                                                                                              (11.27)



                                             Substituting values into equation (11.27) results  *

                                                                      N > E
                                                                        ?PO


                                                                  * *
                                                                                    %
                                                                                                              (11.28)






                                                                            E

                                            11.3.1.1  Filling/evacuating the chamber under upchucked condition

                                                                                            $
                                                             *
                                                                                               
 (
                                                                                %
                                            The flow in the nozzle can became upchucked and it can be analytically solved.
                                                                                    *
                                            Owczarek [1964] found that analytical solution which described here.
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