Page 216 - 48Fundamentals of Compressible Fluid Mechanics
P. 216
178 CHAPTER 10. RAYLEIGH FLOW
Rayleigh Flow
k = 1 4
4
*
T / T
*
T / T
0 0
3 P / P *
*
P P
0 / 0
*
r / r
2
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@( M = ) 1.7143
1
¥
@( M = ) 0.4898
0
0.1 1 10
M
Fri May 6 11:11:44 2005
Fig. 10.3: The basic functions of Rayleigh Flow
4
5
5
7
7 8
8
8
5 :
" " +-"
"-90+1
" )1)
and "-9 5 7 8 : 6 : 6 =),"
:
7 :
9
4
5
5
6 :
7
7 8
8
6
8
"-" "
"
"1"1
9
-"1"
)0+
The exit Mach number is known, the exit pressure can be calculated as
:
5
7 8 :
5 :
7 :
"
For the entrance the stagnation values are
" " +1"
" " ,'
4
5
7
6
5
"
"
"
"1 =),+-9
")
"-+1"
"-9)
9
"-9
can be calculated as the following: 7 9
7 8
: 7 8
68
8
U T
G B I @
The total exit pressure,
"1" "
The heat release (heat transfer) can be calculated from obtaining the stagnation
" )1)
9
"9-)
temperature form the both sides. The stagnation temperature at the entrance,
-9)&"
,
U T
G B I @