Page 347 - 35Linear Algebra
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                          (e) Is there a direction in which displacing the bridge yields no force? If
                              so give a vector in that direction. Briefly evaluate the quality of this
                              bridge design.
                     12. Conic Sections: The equation for the most general conic section is given by

                                                         2
                                            2
                                          ax + 2bxy + dy + 2cx + 2ey + f = 0 .
                         Our aim is to analyze the solutions to this equation using matrices.

                          (a) Rewrite the above quadratic equation as one of the form

                                                                   T
                                                            T
                                                  T
                                                X MX + X C + C X + f = 0

                                                                         x
                                                                                            T
                              relating an unknown column vector X =         , its transpose X , a
                                                                         y
                              2 × 2 matrix M, a constant column vector C and the constant f.
                          (b) Does your matrix M obey any special properties? Find its eigenvalues.
                              You may call your answers λ and µ for the rest of the problem to save
                              writing.
                                  For the rest of this problem we will focus on central conics for
                                  which the matrix M is invertible.
                          (c) Your equation in part (a) above should be be quadratic in X. Recall
                                                                        2
                              that if m 6= 0, the quadratic equation mx + 2cx + f = 0 can be
                              rewritten by completing the square

                                                            c      c
                                                              2   2
                                                    m x +        =    − f .
                                                            m      m
                              Being very careful that you are now dealing with matrices, use the
                              same trick to rewrite your answer to part (a) in the form
                                                           T
                                                         Y MY = g.

                              Make sure you give formulas for the new unknown column vector Y
                              and constant g in terms of X, M, C and f. You need not multiply out
                              any of the matrix expressions you find.
                                  If all has gone well, you have found a way to shift coordinates
                                  for the original conic equation to a new coordinate system
                                  with its origin at the center of symmetry. Our next aim is
                                  to rotate the coordinate axes to produce a readily recognizable
                                  equation.


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