Page 178 - 35Linear Algebra
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178 Determinants
1
.
. .
1 µ
i
S (µ) = . . . .
j
1
. .
.
1
i
Then multiplying M by S (µ) performs a row addition;
j
1
. .
.
. . . . .
.
1 µ
i i j
R R + µR
.
. .
. . . = . . .
.
1 R
j j
R
. . . . .
.
. . .
1
0
i
What is the effect of multiplying by S (µ) on the determinant? Let M =
j
00
i
j
i
S (µ)M, and let M be the matrix M but with R replaced by R Then
j
X j
det M 0 = sgn(σ)m 1 σ(1) · · · (m i σ(i) + µm σ(i) ) · · · m n
σ(n)
σ
X
= sgn(σ)m 1 · · · m i · · · m n
σ(1) σ(i) σ(n)
σ
X j j
+ sgn(σ)m 1 σ(1) · · · µm σ(j) · · · m σ(j) · · · m n
σ(n)
σ
= det M + µ det M 00
00
Since M has two identical rows, its determinant is 0 so
0
det M = det M,
0
when M is obtained from M by adding µ times row j to row i.
Reading homework: problem 3
178