Page 130 - 48Fundamentals of Compressible Fluid Mechanics
P. 130

92                                         CHAPTER 5. NORMAL SHOCK

                                            shock is still. Thus it is the case of shock moving into still medium (suddenly open
                                            valve case). First the Mach velocity ahead the shock has to calculated.




                                                                                   !




                                                   Utilizing POTTO-GDC or that Table (5.4) one can obtain the following table
                                                                                
 %(



                                                                                  # #



                                                                                                 3















                                                   Using the above table, the temperature behind the shock is

                                                                                                      
 3'
                                                                                       3
  *

                                                         
3

                                            In same can be done for the pressure ratio as following  %

                                                                           
  3





                                                                                     #




                                            The velocity behind the shock wave is obtain by utilizing the mass balance as





                                                                                    #


                                                                              *
                                                                                       
 *

                                            Example 5.3:     
  	 	      # # #                     1
                                                                                                          . The static
                                            pressure at the tube is     and (static) temperature of
 
 
  . The gas is brought
                                                                               
 %!( 

 
 
!(/% )(

                                            into complete stop by a sudden by closing a value. Calculate the velocity and the
                                            Gas flows at supersonic velocity in a tube with velocity of ! 
  1
                                            pressure behind the reflecting shock. The specific heat ratio can be assumed to
                                                     .


                                              SOLUTION
                                            be
                                              3  . Then, the prime properties can be found. At this stage the reflecting shock
                                            The first thing which is needed to be done is to find the prime Mach number
                                            velocity is unknown.



                                                   Simply using the Potto-GDC provides for the temperature and velocity the
                                            following table:





                                                                                                      
 )(

                                                                                               0(

                                                   Or if you insist on doing the steps yourself find the upstream prime Mach,
                                                                                       0(
                                                              
 '3    3
                                                                                                              . If this
                                            detail is not sufficient enough that simply utilize the iteration procedure described
                                                       
  !
                                                to be 1.2961. Then using the Table (5.2) you can find the the proper

                                            earlier and obtain
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