Page 53 - 35Linear Algebra
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2.3 Elementary Row Operations                                                                   53


                   Example 22 (Performing EROs with Matrices)


                                                                          
                                     0 1 0      0 1 1 7             2 0 0 4
                                     1 0 0      2 0 0 4        =    0 1 1 7
                                                                          
                                     0 0 1      0 0 1 4             0 0 1 4

                                                                          ∼
                                     1  0 0     2 0 0 4             1 0 0 2
                                                                          
                                     2
                                     0 1 0      0 1 1 7        =    0 1 1 7
                                                                          
                                     0 0 1      0 0 1 4             0 0 1 4
                                                                          ∼

                                                                          
                                    1 0    0    1 0 0 2             1 0 0 2
                                    0 1 −1      0 1 1 7        =    0 1 0 3
                                                                          
                                    0 0    1    0 0 1 4             0 0 1 4

                   Here we have multiplied the augmented matrix with the matrices that acted on rows
                   listed on the right of example 21.


                      Realizing EROs as matrices allows us to give a concrete notion of “di-
                   viding by a matrix”; we can now perform manipulations on both sides of an
                   equation in a familiar way:



                   Example 23 (Undoing A in Ax = b slowly, for A = 6 = 3 · 2)


                                                       6x =       12

                                               ⇔ 3  −1 6x = 3   −1 12
                                               ⇔       2x =        4
                                               ⇔ 2  −1 2x =    2 −1  4

                                               ⇔       1x =        2



                   The matrices corresponding to EROs undo a matrix step by step.





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