Page 260 - 35Linear Algebra
P. 260

260                                                      Orthonormal Bases and Complements


                                                                                T
                            Definition A matrix P is orthogonal if P      −1  = P .

                               Then to summarize,

                            Theorem 14.3.1. A change of basis matrix P relating two orthonormal bases
                            is an orthogonal matrix. I.e.,


                                                                      T
                                                             P  −1  = P .



                                                        Reading homework: problem 2


                                                    3
                            Example 134 Consider R with the ordered orthonormal basis
                                                                 2          1  
                                                                  √        0      √
                                                                   6               3
                                                                  √       √       √   .
                                                               1   1   −1
                                                                   6       2       3
                                            S = (u 1 , u 2 , u 3 ) =    ,    , 
                                                                  −1
                                                                  √       √ 1     √ 1
                                                                   6       2       3
                            Let E be the standard basis (e 1 , e 2 , e 3 ). Since we are changing from the standard
                            basis to a new basis, then the columns of the change of basis matrix are exactly the
                            new basis vectors. Then the change of basis matrix from E to S is given by
                                                                                        
                                                                    e 1 u 1 e 1 u 2 e 1 u 3
                                                 j
                                          P = (P ) = (e j · u i ) =   e 2 u 1 e 2 u 2 e 2 u 3  
                                                i
                                                                    e 3 u 1 e 3 u 2 e 3 u 3
                                                                    2        1  
                                                                    √     0   √
                                                                      6        3
                                                                  1     1   −1
                                              = u 1 u 2 u 3         √    √    √   .
                                                                      6   2    3
                                                              = 
                                                                    −1
                                                                    √    √ 1  √ 1
                                                                      6   2    3
                               From our theorem, we observe that
                                                                    T  
                                                                    u
                                                                     1
                                                                    u
                                                  P −1  = P  T  =   T 
                                                                     2
                                                                    u T
                                                                     3
                                                                    2   1    −1  
                                                                    √    √    √
                                                                     6    6    6
                                                                     0           .
                                                                        √ 1  √ 1 
                                                                          2    2
                                                              = 
                                                                    √ 1  −1   √ 1
                                                                         √
                                                                     3    3    3
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