Page 247 - 35Linear Algebra
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13.3 Changing to a Basis of Eigenvectors                                                      247


                   Definition A matrix M is diagonalizable if there exists an invertible ma-
                   trix P and a diagonal matrix D such that

                                                   D = P  −1 MP.

                      We can summarize as follows.
                      • Change of basis rearranges the components of a vector by the change
                         of basis matrix P, to give components in the new basis.

                      • To get the matrix of a linear transformation in the new basis, we con-
                         jugate the matrix of L by the change of basis matrix: M 7→ P   −1 MP.

                      If for two matrices N and M there exists a matrix P such that M =
                   P  −1 NP, then we say that M and N are similar. Then the above discussion
                   shows that diagonalizable matrices are similar to diagonal matrices.

                   Corollary 13.3.1. A square matrix M is diagonalizable if and only if there
                   exists a basis of eigenvectors for M. Moreover, these eigenvectors are the
                   columns of a change of basis matrix P which diagonalizes M.


                                               Reading homework: problem 2

                   Example 132 Let’s try to diagonalize the matrix

                                                                   
                                                    −14 −28 −44
                                             M =    −7 −14 −23      .
                                                       9    18   29

                   The eigenvalues of M are determined by
                                                                2
                                                           3
                                         det(M − λI) = −λ + λ + 2λ = 0.
                   So the eigenvalues of M are −1, 0, and 2, and associated eigenvectors turn out to be

                                                                        
                                          −8            −2                 −1
                                   v 1 =   −1   , v 2 =    1   , and v 3 =   −1   .
                                           3              0                 1

                   In order for M to be diagonalizable, we need the vectors v 1 , v 2 , v 3 to be linearly
                   independent. Notice that the matrix

                                                                         
                                                             −8 −2 −1

                                        P = v 1 v 2 v 3 =   −1     1 −1  
                                                               3    0   1

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