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2.3 Basic structure types


                 Pauling rules: understanding polyhedral structures









                    Example 4 – Al O *2SiO *2H O (Kaolinite)
                                                    3
                                                2
                                                                         2
                                                                2
                              3+
                                                   4+
                    CN(Al ) = 6, CN(Si ) = 4, sij (Al-O) = 1/2 , sij (Si-O) = 1
                    CN(O1) = 2(Al), CN(O2) = 2(Al) + 1(Si), CN(O3) = 2


                    sij (O1) = 1 (!!!), sij (O2) = 2, sij (O3) = 2. Consequence: O1 is OH !!!





                    Example 5 – Determine possible coordination spheres of O in Na BiO                                                                 4
                                                                                                                                              3

                                                                                                                                 5+
                    • rock salt type structure CN(O) = 6, CN(cations) = 6, O , Na , Bi .
                                                                                                                 2-
                                                                                                                          +
                    • ONa with charge: -2 + 6/6 = -1
                             6

                    • ONa Bi with charge: -2 + 5/6 + 5/6 = -1/3
                             5

                    • ONa Bi with charge: -2 + 4/6 + 10/6 = +1/3
                                  2
                             4
                    • ONa Bi with charge: -2 + 3/6 + 15/6 = +1
                             3
                                  3
                    • Composition and frequency of octahedra:



                      O(Na Bi)/6 + O(Na Bi )/6 = O Na Bi                          3/6  = O Na Bi
                                                                                                  3
                                                                                            4
                                                         2
                                                    4
                              5
                                                                           9/6
                                                                     2
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