Page 184 - 48Fundamentals of Compressible Fluid Mechanics
P. 184

146                                           CHAPTER 9. FANNO FLOW
                                            9.4.1   Example                            6879;:=<  ?A@&BC=D





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                                                                                                    EGF







                                                                   Fig. 9.3: Schematic of example 1  .0/$12-345   "!$#&%('  )*+-,
                                            Example 9.1:
                                            Air flows from a reservoir and enters a uniform pipe with a diameter of 0.05 [m]
                                            and length of 10 [m]. The air exits to the atmosphere. The following conditions
                                                                                                       4
                                                                                                       . Assume that
                                                                                  and that the flow from the reservoir up

                                                                        temperature L MH (*
ON
                                                                                                PHRQS
                                            prevail at the exit:  8HJI K
                                            to the pipe inlet is essentially isentropic. Estimate the total temperature and total

                                                                               QUQ=V
                                            the average friction factor to be HTQ0S
                                            pressure in the reservoir under the Fanno flow model.

                                              SOLUTION
                                            For isentropic flow to the pipe inlet, temperature and total pressure at the pipe inlet
                                            are the same as the those in the reservoir. Thus, finding the total pressure and
                                            temperature at the pipe inlet is the solution. With the Mach number and temper-
                                            ature known at the exit, the total temperature at the entrance can be obtained by
                                                                                          ) the following is obtained.

                                            knowing the WYX(Z [
                                                           . For given Mach number (N H\QS












                                                                              I
S Q
Q
                                                      Q^S Q
QUQ
Q
                                                              Q0S Q0I-V  I I=S_I
                                                   So the total temperature at the exit    I=S Q      QS I-V ]  ] 
  I
S Q
                                                                          I % 
 V 3 
 (
                                                                     L

                                                                                
 QUQ
                                                                                   H &
                                                                  H
                                                                                         Q0S
                                                                          L  H
                                                              L
                                                                      L

                                                                                          is added as





                                                   To ”move” the other side of the tube the W`XaZ [
                                                                               IUS Q
 (
                                                                           V
                                                                                      I(Q
                                                                               QS Q
Q=V
                                                                                         QS QI-V  I 
 S I
                                                      WYX(Z [ cb H W`XaZ [  WYXaZ [  H

                                              4 This property is given only for academic purposes. There is no Mach meter.


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                                                                                QS Q
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