Page 41 - 35Linear Algebra
P. 41

2.1 Gaussian Elimination                                                                        41


                   called the Identity Matrix, since this would give the simple statement of a
                   solution x = a, y = b. The same goes for larger systems of equations for
                   which the identity matrix I has 1’s along its diagonal and all off-diagonal
                   entries vanish:


                                                                  
                                                     1 0 · · · 0
                                                     0 1        0
                                                                  
                                              I =  . .     . .  . . 
                                                                   
                                                  
                                                   .         .  . 
                                                     0 0 · · · 1



                                               Reading homework: problem 2


                   For many systems, it is not possible to reach the identity in the augmented
                   matrix via Gaussian elimination. In any case, a certain version of the matrix
                   that has the maximum number of components eliminated is said to be the
                   Row Reduced Echelon Form (RREF).

                   Example 13 (Redundant equations)

                                       )              !            !    (
                      x   +   y   = 2         1 1 2         1 1 2          x + y = 2
                                          ⇔             ∼             ⇔
                     2x + 2y = 4              2 2 4         0 0 0          0 + 0 = 0

                   This example demonstrates if one equation is a multiple of the other the identity
                   matrix can not be a reached. This is because the first step in elimination will make
                   the second row a row of zeros. Notice that solutions still exists (1, 1) is a solution.
                   The last augmented matrix here is in RREF; no more than two components can be
                   eliminated.

                   Example 14 (Inconsistent equations)

                                       )              !            !    (
                      x   +   y   = 2         1 1 2         1 1 2          x + y = 2
                                          ⇔             ∼             ⇔
                     2x + 2y = 5              2 2 5         0 0 1          0 + 0 = 1

                   This system of equation has a solution if there exists two numbers x, and y such that
                   0 + 0 = 1. That is a tricky way of saying there are no solutions. The last form of the
                   augmented matrix here is the RREF.


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