Page 29 - 35Linear Algebra
P. 29

1.4 So, What is a Matrix?                                                                       29


                   Example 10 of how a different matrix comes into the same linear algebra problem.


                   Another possible notational convention is to

                                                                   
                                                                    a
                                          denote a + bx + cx 2  as     .
                                                                    b
                                                                    c
                                                                      B 0
                   With this alternative notation

                                               
                                                a

                                      d                   d                   2
                                                b
                                         + 2        =      + 2 (a + bx + cx )
                                      dx                  dx
                                                c
                                                   B 0
                                                        2
                            = (b + 2cx) + (2a + 2bx + 2cx ) = (2a + b) + (2b + 2c)x + 2cx 2
                                                                 
                                          2a + b           2 1 0       a
                                     =    2b + 2c    =   0 2 2        .
                                                                       b
                                            2c             0 0 2       c
                                                   B 0                     B 0
                   Notice that we have obtained a different matrix for the same linear function. The
                   equation we started with

                                                                         
                                                         2 1 0      a           1
                                 d

                                    + 2 f = x + 1 ⇔    0 2 2          =   
                                                                     b
                                                                                1
                                 dx
                                                         0 0 2       c          0
                                                                         B 0      B 0
                                                       2a + b = 1
                                                  ⇔ 2b + 2c = 1
                                                          2c = 0
                                    
                                     1
                                     4
                   has the solution  . Notice that we have obtained a different 3-vector for the
                                    1 
                                     2
                                     0
                                                                 0
                                                                                            1
                   same vector, since in the notational convention B this 3-vector represents  1  + x.
                                                                                        4   2
                      One linear function can be represented (denoted) by a huge variety of
                   matrices. The representation only depends on how vectors are denoted as
                   n-vectors.


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