Page 228 - 35Linear Algebra
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228                                                               Eigenvalues and Eigenvectors




























                            It was picked at random by choosing a pair of vectors L(e 1 ) and L(e 2 ) as
                            the outputs of L acting on the canonical basis vectors. Notice how the unit
                            square with a corner at the origin is mapped to a parallelogram. The second
                            line of the picture shows these superimposed on one another. Now look at the
                            second picture on that line. There, two vectors f 1 and f 2 have been carefully
                            chosen such that if the inputs into L are in the parallelogram spanned by f 1
                            and f 2 , the outputs also form a parallelogram with edges lying along the same
                            two directions. Clearly this is a very special situation that should correspond
                            to interesting properties of L.
                               Now lets try an explicit example to see if we can achieve the last picture:

                            Example 126 Consider the linear transformation L such that

                                                    1       −4            0      3
                                                L      =          and L      =      ,
                                                    0      −10            1      7
                            so that the matrix of L in the standard basis is


                                                                −4 3
                                                                        .
                                                              −10 7

                                                                                        1      0
                            Recall that a vector is a direction and a magnitude; L applied to  or  changes
                                                                                        0      1
                            both the direction and the magnitude of the vectors given to it.
                               Notice that

                                                     3       −4 · 3 + 3 · 5    3
                                                  L     =                   =      .
                                                     5      −10 · 3 + 7 · 5    5
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