Page 112 - 35Linear Algebra
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112                                                                      Linear Transformations


                            6.1     The Consequence of Linearity


                            Now that we have a sufficiently general notion of vector space it is time to
                            talk about why linear operators are so special. Think about what is required
                            to fully specify a real function of one variable. One output must be specified
                            for each input. That is an infinite amount of information.
                               By contrast, even though a linear function can have infinitely many ele-
                            ments in its domain, it is specified by a very small amount of information.

                            Example 69 (One output specifies infinitely many)
                            If you know that the function L is linear and that


                                                               1       5
                                                            L      =
                                                               0       3
                            then you do not need any more information to figure out


                                                  2        3       4       5
                                               L     , L      , L     , L     , etc . . . ,
                                                  0        0       0       0
                            because by homogeneity


                                               5          1           1       5      25
                                           L      = L 5        = 5L      = 5     =        .
                                               0          0           0       3      15
                            In this way an an infinite number of outputs is specified by just one.

                                                          2
                            Example 70 (Two outputs in R specifies all outputs)
                            Likewise, if you know that L is linear and that


                                                      1      5           0      2
                                                   L     =       and L      =
                                                      0      3           1      2
                            then you don’t need any more information to compute


                                                                   1
                                                                L
                                                                   1
                            because by additivity


                                      1         1      0         1        0      5      2      7
                                  L      = L       +       = L      + L      =      +      =      .
                                      1         0      1         0        1      3      2      5
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