Page 33 - slides.dvi
P. 33

•
                                                                                                  •
                               •
                                                                                           •
                                                                               For
                  SJF
                                                                                                               SJF
             given
   Operating
                  is
                                                                                           Use
                                                                                      used
                                                                                                        Intuition
             set
                                                                                      to
                               Waiting
                        Average
   Systems
             of
                                                                                                  Associate
                                                                                           these
                                                                               example:
   —
                                                                                                        from
                  optimal
                               time
   CPU
                                                                                      break
                  in
                                                                                                  with
                        waiting
                               for
                                                                                                               Scheduling
                                                                                                        FCFS
                                                                                           lengths
                  the
                                       0
             processes.
                                                                                      ties).
                                                                                                  each
   Scheduling
                                                                                           to
             .
                        time:
             .
                                                                                                        leads
                               P 1 =0;
                  sense
                        (0
                                                                                                        us
                                                   P 4
                                             P
                                                        P 3
                                                                  P 1
                                                             P 2
                                            1
                        +
                                                                                                  process
                                                                        Process
                                                                                                        to
                  that
                        6
                                                                                           schedule
                               P 2 =6;
                  it
                        +
                                                                                                  the
                        3
                                                                                           the
                        +
                  gives
                                       7
                               P 3 =3;
                                                                                                        shortest
                                                                        Arrival
                                                        4
                                                   5
                                                             2
                                                                  0
                                             P
                                            3
                                                                                                  length
                                       8
                        7)/4
                  the
                                                                                           process
                                                                                                  of
                                                                                                        job
                        =
                                                                        Time
                                             P
                                            2
                                                                                                  its
                               P 4 =7;
                        4.
                                                                                           with
                                                                                                        first
                                                                                                  next
                                                                                           the
                                       12
                  minimum
                                                                        Burst
                                                                  7
                                                             4
                                                   4
                                                        1
                                                                                                        (SJF)
                                                                                                  CPU
                                             P
                                            4
                                                                        Time
                                                                                           shortest
                  average
                                       16
                                                                                                  burst.
                                                                                           time
                                                                                                        scheduling.
                  waiting
                                                                                           (FCFS
                  time
                                                                                           can
                  for
                                                                                           be
                  any
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